4[-[3(c+1)-2(c+1)]]=-2c

Solution for 4[-[3(c+1)-2(c+1)]]=-2c equation:

Simplifying
4[-1[3(c + 1) + -2(c + 1)]] = -2c

Reorder the terms:
4[-1[3(1 + c) + -2(c + 1)]] = -2c
4[-1[(1 * 3 + c * 3) + -2(c + 1)]] = -2c
4[-1[(3 + 3c) + -2(c + 1)]] = -2c

Reorder the terms:
4[-1[3 + 3c + -2(1 + c)]] = -2c
4[-1[3 + 3c + (1 * -2 + c * -2)]] = -2c
4[-1[3 + 3c + (-2 + -2c)]] = -2c

Reorder the terms:
4[-1[3 + -2 + 3c + -2c]] = -2c

Combine like terms: 3 + -2 = 1
4[-1[1 + 3c + -2c]] = -2c

Combine like terms: 3c + -2c = 1c
4[-1[1 + 1c]] = -2c
4[[1 * -1 + 1c * -1]] = -2c
4[[-1 + -1c]] = -2c
[-1 * 4 + -1c * 4] = -2c
[-4 + -4c] = -2c

Solving
-4 + -4c = -2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '2c' to each side of the equation.
-4 + -4c + 2c = -2c + 2c

Combine like terms: -4c + 2c = -2c
-4 + -2c = -2c + 2c

Combine like terms: -2c + 2c = 0
-4 + -2c = 0

Add '4' to each side of the equation.
-4 + 4 + -2c = 0 + 4

Combine like terms: -4 + 4 = 0
0 + -2c = 0 + 4
-2c = 0 + 4

Combine like terms: 0 + 4 = 4
-2c = 4

Divide each side by '-2'.
c = -2

Simplifying
c = -2